16c^2+22c-3=0

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Solution for 16c^2+22c-3=0 equation:


Simplifying
16c2 + 22c + -3 = 0

Reorder the terms:
-3 + 22c + 16c2 = 0

Solving
-3 + 22c + 16c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(-3 + -2c)(1 + -8c) = 0

Subproblem 1

Set the factor '(-3 + -2c)' equal to zero and attempt to solve: Simplifying -3 + -2c = 0 Solving -3 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -2c = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -2c = 0 + 3 -2c = 0 + 3 Combine like terms: 0 + 3 = 3 -2c = 3 Divide each side by '-2'. c = -1.5 Simplifying c = -1.5

Subproblem 2

Set the factor '(1 + -8c)' equal to zero and attempt to solve: Simplifying 1 + -8c = 0 Solving 1 + -8c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -8c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -8c = 0 + -1 -8c = 0 + -1 Combine like terms: 0 + -1 = -1 -8c = -1 Divide each side by '-8'. c = 0.125 Simplifying c = 0.125

Solution

c = {-1.5, 0.125}

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